Question: N-Butane is converted to isobutene in a continuous isomerization reactor that operates isothermally at 149C. The feed to the reactor contains 93 mole% n-butane, 5%
N-Butane is converted to isobutene in a continuous isomerization reactor that operates isothermally at 149°C. The feed to the reactor contains 93 mole% n-butane, 5% isobutene, and 2% HC1 at 149°C, and a 40% conversion of n-butane is achieved.
(a) Taking a basis of 1 mol of feed gas calculate the moles of each component of the feed and product mixtures and the extent of reaction (mol).
(b) Calculate the standard heat of the isomerization reaction (kJ/mol). Then, taking the feed and product species at 25°C as references, prepare an inlet—outlet enthalpy table and calculate and fill in the component amounts (mol) and specific enthalpies (kJ/mol).
(c) Calculate the required rate of heat transfer (kJ) to or from the reactor (state which it is). Then determine the required heat transfer rate (kW) for a reactor feed of 325mol/h.
(d) Use your calculated results to determine the heat of the isomerization reaction at 149°C, ΔHг (149°C) (kJ/mol).
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a b nC4H0g iC4H0g Basis 1 mol feed gas 0930 mol nC4H10 0050 mol ... View full answer
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