5 liters of air with a humidity of 0.6, a temperature of 20 ° C and a pressure of 75 cm Hg it is pressed together to 2 liters at a temperature of 25 ° C.

Calculate all missing state parameters, the mass of dry air and the masses of water vapor and water in each state.

Bee what volume at 25 ° C is the considered air saturated with water vapor?

The atmosphere\'s air consists of approximately 78% by volume nitrogen gas, 21% by volume oxygen gas and almost 1% argon.

Air has a theoretical molar mass of 28.97 g / mol.

Table of Maximum pressure, density for water and saturated water vapor

Transcribed Image Text:

T PL (kg/m3) 999,8 pmax pverz (°C) (bar) 0,00609 0,00866 0,01226 0,0169 0,0233 0,0317 0,0424 0,0561 0,0737 0,0957 0,1232 0,157 0,200 0,250 0,312 0,385 0,473 0,577 0,700 0,844 1,013 1,207 1,432 1,688 1,984 2,319 (kg/m3) 0,00485 0,00680 0,00940 0,0128 0,0173 0,0230 0,0304 0,0396 0,0511 0,0654 0,0830 0,104 0,130 0,161 0,198 0,242 0,293 0,353 0,424 0,505 0,595 0,705 0,827 0,965 1,122 1,30 5 1000 10 999,6 15 999 20 998 25 997 30 996 35 994 40 992 45 990 988 986 50 55 60 983 980 978 65 70 75 975 972 80 85 969 90 965 95 962 100 958 105 955 110 951 115 947 120 943 125 939 T PL (kg/m3) 999,8 pmax pverz (°C) (bar) 0,00609 0,00866 0,01226 0,0169 0,0233 0,0317 0,0424 0,0561 0,0737 0,0957 0,1232 0,157 0,200 0,250 0,312 0,385 0,473 0,577 0,700 0,844 1,013 1,207 1,432 1,688 1,984 2,319 (kg/m3) 0,00485 0,00680 0,00940 0,0128 0,0173 0,0230 0,0304 0,0396 0,0511 0,0654 0,0830 0,104 0,130 0,161 0,198 0,242 0,293 0,353 0,424 0,505 0,595 0,705 0,827 0,965 1,122 1,30 5 1000 10 999,6 15 999 20 998 25 997 30 996 35 994 40 992 45 990 988 986 50 55 60 983 980 978 65 70 75 975 972 80 85 969 90 965 95 962 100 958 105 955 110 951 115 947 120 943 125 939

Answer rating: 100% (QA)

From ideal gas equation we know that PVnRT Here V is volume P is pressure and T is Tem... View the full answer