5. The answer is True. However, Please provide a more clear solution and explanation to justify the answer. You may need outside sources thanks.

T if the equivalence ratio in ethane combustion is 0.90, stoichiometry predicts (for a very high value of the equilibrium constant) that the mole fraction of H20 does not exceed 15%. (35X376) Cito - 35 g + (1351376 + N 0.92 226 + 34,0 +0.79 0.9 0.9 (2+3165132 +0,39) 3 B5 3+ 2015 (- 0,1499) / 0.9