5. The store offers overtime to assembly workers. This will increase the time available for bike- assembly. What change in the model is needed if one additional hour is available for assembly?

1. 5M1+6M2+4M3+4M4+1
2. (5+1)M1+6M2+4M3+4M4 >= 1201
3. 5M1+6M2+4M3+4M4
4. M1+M2+M3+M4

6. Assume the combined order must exceed only 265 (not 275). Is the current optimal solution still feasible? That is, are all the constraints still satisfied?

1. No. It will violate the assembly time constraint.
2. No. The current solution purchases 275 bikes. This will have to change if you no longer allow 275 bikes to be purchased.
3. Yes. The current solution purchases 275 bikes. The new constraint is Combine order >=265. The current optimal solution can stay.
4. Impossible to know. We must re-run.

7. How much assembly time remn unused under the current optimal solution?

1. All of the assembly time is used.
2. Most of the assembly time remains unused: 1200-5-6-4-4.
3. The total assembly time per unit = (5+6+4+4) = 19 The average number of bikes = (40+30+175+30)/4 = 68.75 The assembly time used is 19*68.75 = about 1306 hours. Time left = 1306 1200.

8. Management decided to add a constraint to the problem, as follows: The amount of time spent on assembly of M1 and M2 combined should not exceed twice the amount of time spent on assembly of M3 and M4 combined. Which option below reflect this requirement? See choices on the next page.

1. M1
2. M1
3. M1+M2
4. None of the above

4 M1 40 30 M2 30 25 M3 175 M4 30 20 22 1 = 500 1200 275 30 30 30 1 >= 1 1 >= 13 Min M4 1 20 30 4 M1 40 30 M2 30 25 M3 175 M4 30 20 22 1 = 500 1200 275 30 30 30 1 >= 1 1 >= 13 Min M4 1 20 30