Question: 5cm q1 = 10HC 92 = - 5HC 10cm 2. Two charges are located on the x-axis, one at x = 0cm, and the other

 5cm q1 = 10HC 92 = - 5HC 10cm 2. Two

5cm q1 = 10HC 92 = - 5HC 10cm 2. Two charges are located on the x-axis, one at x = 0cm, and the other x = 10cm. Their charges are shown in the figure above. (a) Find the electric field vector at the point (0cm,5cm).(4pt) (b) If a 5/C charge is placed at the point (Ocm,5cm), what is the magnitude and direction of the force on that charge? What if it is a -5/C charge?(1pt)

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