Question: 6 2V - (1/2) + X DH, = 10 kJ/mol (3/2) + 4X -- 2V + X + 3Y DH2 = -30 kJ/mol of Z

6 2V - (1/2) + X DH, = 10 kJ/mol (3/2) + 4X -- 2V + X + 3Y DH2 = -30 kJ/mol of Z +4V - X DHz - 20 kJ/mol stion Calculate DH for: X - Z + 3Y Select one: O a. 0 kJ/mol Ob. 10 kJ/mol O c.-10 kJ/mol O d. -20 kJ/mol O e. 20 kJ/mol

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