$6\mathrm{.}5$ A five$-$sided closed field traverse has the following distances in meters: $AB=51\mathrm{.}766$; $BC=26\mathrm{.}947$;$CD=37\mathrm{.}070$;$DE=35\mathrm{.}292$; $EA=19\mathrm{.}192.$ The adjusted angles are as follows: $A=101{03}^{\text{'}}{19}^{\text{'}\text{'}}$;$B=101{41}^{\text{'}}{49}^{\text{'}\text{'}}$;$C=102{22}^{\text{'}}{03}^{\text{'}\text{'}}$;$D=115{57}^{\text{'}}{20}^{\text{'}\text{'}}$;$E=118{55}^{\text{'}}{29}^{\text{'}\text{'}}.$ The bearing of $AB$ is $N{00}^{\text{'}}{00}^{\text{'}\text{'}}E.BC$ is in the S$.$E$.$ quadrant.

a$.$ Compute the bearings or the azimuths.

b$.$ Compute the latitudes and departures.

c$.$ Determine the linear error of closure and the accuracy ratio.