$6=6,67{10}^{-11}$

PR$\mathrm{.}3.$ A satellite of $300-kg$ mass is in a circular orbit of $1\mathrm{.}2{10}^{7}m$ radius, about the planet Roton. Period of the satellite is $2\mathrm{.}8$ h $.$

$\frac{15.G.An2}{(1\mathrm{.}210{)}^2}=Ms$

$a$

b$)$ Determine the acceleration of the satellite. $=\frac{3{10}^6}{\frac{7}{10}}=\frac{3}{7}{10}^7$

$\frac{6^2}{R}=>\frac{(4\mathrm{.}2{10}^6{)}^2}{{7\mathrm{.}170}^7}$

$a=\frac{6^2}{R}=>\frac{(4\mathrm{.}2{10}^6{)}^2}{1\mathrm{.}2{10}^7}$

$=\frac{.2_2^2{10}^{18}\frac{41}{21}}{3}=14,7{10}^5$

c$)$ Determine the gravitation force acting on the satellite.

$F=(G*s*R{)}^{?}$

d$)$ Determine the mass of planet Roton.

e$)$ The radius of planet Roton is $5\mathrm{.}0{10}^{6}m.$ What is the acceleration of gravity, g $,$ at the surface of planet Roton?