Question: 6. Assume a computer that has 16 8-bit registers, 64kB byte-addressable memory (meaning that each byte has a unique address) and can perform 128 distinct

 6. Assume a computer that has 16 8-bit registers, 64kB byte-addressable

6. Assume a computer that has 16 8-bit registers, 64kB byte-addressable memory (meaning that each byte has a unique address) and can perform 128 distinct operations. Given the following register-memory instruction format: C)I REG MEM How many bits are needed to properly express such an instruction? Note: OP stands for the code of the operation to be performed, REG stands for the index of the register to be used and MEM stands for the address of the 8-bit memory words to be used

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