Question: 6. CoinChange(d, N) 1. n = length[d] 2. for i = 1 ton 3. C[i,0) = 0 4. for i = 1 ton for j

6. CoinChange(d, N) 1. n = length[d] 2. for i =

6. CoinChange(d, N) 1. n = length[d] 2. for i = 1 ton 3. C[i,0) = 0 4. for i = 1 ton for j = 1 to N if i = 1 and j 1, and 1 1, and 1

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