Question: - 6 hole, vertical well with bit on bottom - 1 9 , 0 0 0 ft . TD , MW = 1 3

-6" hole, vertical well with bit on bottom
-19,000 ft. TD, MW =13.8 ppg
-95/8",47#/ft. casing set at 9,000 ft.
-7" Liner, 26#/ft. set at 14,000 ft. with a 300 ft. overlap inside the 95/8" casing
-4",14 #/ft. drillpipe
-1,160 ft. of 4" HWDP (Heavy Weight Drill Pipe),27.2 #/ft.
-550 ft. of 43/4" Drill Collars
-5" x 10" triplex pump at 91% efficiency and 90 strokes/min
-3 mud pits. Each is 27 ft. x 10 ft. x 11 ft. deep. Each contains 10 ft. of mud when the drillstring is in the hole.
q1-Consider the same well drawn in previous problem.
After drilling an additional 600 ft. of formation, the Company Man decides to POOH (Pull out of hole) and check the bit.
Calculate the new volume distribution when we have the bit at surface considering the following as well:
-Mud lost over the shakers (while drilling the 600 ft. of new formation)=20 bbl
-30 bbl of Base Oil was added - assume mud weight change negligible
q1-Surface volume (pit volume)_____________ bbl
1133.84
1331.48
1381.96
1431.84
Drill string volume _____________ bbl
0
197.55
204.05
214.50
Hole volume ________ bbl
1053.49
1035.94
1040.94
1025.94
Hydrostatic pressure at the 7" liner shoe ____________ psi
12460.6
10046.4
10640.6
11243.6
Hydrostatic pressure at bottom ____________ psi
10046.4
14064.96
10640.6
12460.6

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