Question: 6) Words were displayed on a computer screen with background colors of red and blue. Results from scores on a test of word recall are

6) Words were displayed on a computer screen with background colors of red and blue. Results from scores on a test of word recall are given below. Use a 0.05 significance level to test the claim that the samples are from populations with the same standard deviation. Assume that both samples are independent simple random samples from populations having normal distributions. Does the background color appear to have an effect on the variation of word recall scores? n S Red Background 34 15.45 5-5 Blue Background 36 12.45What are the null and alternative hypotheses? OA. Ho: 07 = 02 OB. Ho: 01#02 2 H1: 07 202 H1:09

Words were displayed on a computer screen with background colors of red and blue. Results from scores on a test of word recall are given below. Use a 0.05 significance level to test the claim that the samples are from populations with the same standard deviation. Assume that both samples are independent simple random samples from populations having normal distributions. Does the background color appear to have an effect on the variation of word recall scores? n S Red Background 34 15.45 5-5 Blue Background 36 12.45What are the null and alternative hypotheses? OA. Ho: 07 = 02 OB. Ho: 01#02 2 H1: 07 202 H1:09 =02 OC. Ho: 01 =02 OD. Ho: 07 2 = 02 2 H1:0 P2 H1 : P1 7 P2 OD. Ho: P1 SP2 OE. Ho: P1 = P2 OF. Ho: P1 # P2 H1: P1 # P2 H1 : P1 = P2 H1: P1 = P2 Identify the test statistic. Z= 0.14 (Round to two decimal places as needed.) Identify the P-value. P-value = 0.00 (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? The P-value is less than the significance level of a = 0.01, so reject the null hypothesis. There is sufficient evidence to support the claim that the proportion of people over 55 who dream in black and white is greater than the proportion for those under 25. b. Test the claim by constructing an appropriate confidence interval. The 98% confidence interval is 1.094

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