8.00 mL of vinegar solution is titrated with 39.0 mL of 0.20 M NaOH. Calculate the...

 

 

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8.00 mL of vinegar solution is titrated with 39.0 mL of 0.20 M NaOH. Calculate the mass percent of acetic acid (Molar mass = 60.05 g/mol) in vinegar. Assume the density of the vinegar is 1.00 g/ml. O a. 7.81% O b. 5.20% O c. 6.69% O d. 9.37% e. 5.85% Given that: 2H202(1)2H20(g) + O2(g) AH = -176.0 kJ; 2H2(g) + 02(g) → 2H20(g) AH = -548.8 kJ. Use Hess's law to calculate AH for the reaction: H202(1) → H2(g) + 02(g). O a. +196.4 kJ/mol O b. +181.4 kJ/mol O C. +191.4 kJ/mol d. +176.4 kJ/mol e. +186.4 kJ/mol 8.00 mL of vinegar solution is titrated with 39.0 mL of 0.20 M NaOH. Calculate the mass percent of acetic acid (Molar mass = 60.05 g/mol) in vinegar. Assume the density of the vinegar is 1.00 g/ml. O a. 7.81% O b. 5.20% O c. 6.69% O d. 9.37% e. 5.85% Given that: 2H202(1)2H20(g) + O2(g) AH = -176.0 kJ; 2H2(g) + 02(g) → 2H20(g) AH = -548.8 kJ. Use Hess's law to calculate AH for the reaction: H202(1) → H2(g) + 02(g). O a. +196.4 kJ/mol O b. +181.4 kJ/mol O C. +191.4 kJ/mol d. +176.4 kJ/mol e. +186.4 kJ/mol