$7-18.$ Use the following data to calculate the standard molar entropy of cyclopropane at $298\mathrm{.}15K.$

$C_P\frac{C_3{H}_6((s))}{R}=-1\mathrm{.}921+(0\mathrm{.}1508K^{-1})T-(9\mathrm{.}670{10}^{-4}{K}^{-2})T^2$

$+(2\mathrm{.}694{10}^{-6}{K}^{-3})T^3$

$15KT145\mathrm{.}5K$

$C_P\frac{C_3{H}_6(l)}{R}=5\mathrm{.}624+(4\mathrm{.}493{10}^{-2}{K}^{-1})T-(1\mathrm{.}340{10}^{-4}{K}^{-2})T^2$

$145\mathrm{.}5KT240\mathrm{.}3K$

$C_P\frac{C_3{H}_6((g))}{R}=-1\mathrm{.}793+(3\mathrm{.}277{10}^{-2}{K}^{-1})T-(1\mathrm{.}326{10}^{-5}{K}^{-2})T^2$

$240\mathrm{.}3KT1000K$

$T_{\text{f}\text{u}\text{s}}=145\mathrm{.}5K,T_{\text{v}\text{a}\text{p}}=240\mathrm{.}3K,\frac{{}_{\text{f}\text{u}\text{s}}}{b}ar(H)=5\mathrm{.}44kJ*mo{l}^{-1},\frac{{}_{\text{v}\text{a}\text{p}}}{b}ar(H)=20\mathrm{.}05kJ*mo{l}^{-1},$ and ${}_D=130K.$ The correction for nonideality $=0\mathrm{.}54J*K^{-1}*mo{l}^{-1}.$

$7-19.$ Use the data in Problem $7-18$ to plot the standard molar entropy of cyclopropane from $0K$ to $1000K.$