Question: 7. Review. Three forces acting on an object are given by F = -(-2.001 +2.003) N, and F = (5.001-3.003) N, and F, = (-45.01)
7. Review. Three forces acting on an object are given by F = -(-2.001 +2.003) N, and F = (5.001-3.003) N, and F, = (-45.01) N. The object experiences an acceleration of magnitude 3.75 m/s. (a) What is the direction of the acceleration? Answer (b) What is the mass of the object? Answer (c) If the object is initially at rest, what is its speed after 10.0 s? Answer (d) What are the velocity components of the object after 10.0 s? Answer # AA A
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