Question: Three forces acting on an object are given by F = (-1.91 + 5.501) N, F = (4.951 - 1.51) N, and F3 =

Three forces acting on an object are given by F = (-1.91 

Three forces acting on an object are given by F = (-1.91 + 5.501) N, F = (4.951 - 1.51) N, and F3 = (-501) N. The object experiences an acceleration of magnitude 3.50 m/s. (a) What is the direction of the acceleration? 4.87 x Note that the direction of the acceleration is the same as the direction of the net force. (counterclockwise from the +x-axis) (b) What is the mass of the object? 13.46 kg (c) If the object is initially at rest, what is its speed after 15.0 s? 52.5 m/s (d) What are the velocity components of the object after 15.0 s? (Let the velocity be denoted by v.) v = -52.2 + 4.35 If the initial velocity is zero, a constant acceleration will generate a velocity oriented in the same direction as the acceleration.j) m/s

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