7.15. A control chart indicates that the current process fraction nonconforming is 0.02. If 50 items are inspected each day, what is the probability of detecting a shift in the fraction nonconforming to 0.04 on the first day after the shift? By the end of the third day following the shift? P -0.02;n - 50 UCL=p+3,p(1-p) =0.02+ 3,/0.02(1-0.02)/50 =0.0794 LCL =p-3, p(1-p) =0.02-3,/0.02(1-0.02)/50 =0.02-0.0594=0 Since Pnew = 0.04