Question: 8 8. A Web Usage Snapshot indicated a monthly average of 41 Internet visits of a particular website per user from home. A random sample

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8 8. A Web Usage Snapshot indicated a monthly average of 41

8. A Web Usage Snapshot indicated a monthly average of 41 Internet visits of a particular website per user from home. A random sample of 25 Internet users yielded a sample mean of 43 visits with a standard deviation of 5.3. At the 0.10 level of significance, can it be concluded that this differs from the national average? Assume the population is normally distributed. [7 marks] a) What test should be performed (z or t)? b) Find the critical value(s). c) Calculate the test statistic d) Make a decision. a) or b) ? Circle a) if you choose to "Reject the null hypothesis" Circle b) if you choose to "Fail to reject the null hypothesis". e) Choose the correct conclusion (Circle 1 or 2): 1. At 5% level of significance, there is not enough evidence to support the claim that the mean is different from the national average. 2. At 5% level of significance, there is enough evidence to support the claim that the mean is different from the national average

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