(8%) Problem 1: Two parallel plates have charges +Q and -Q, as shown. The magnitude of the charges is 39.2 n, the area of each plate is A = 0.0253 ma, and the distance between them is d d - 7.88 cm. The plates are surrounded by air. A +Q Q Otheexpertta.com 4 14% Part (a) Express the capacitance of this parallel-plate capacitor in terms of vacuum permittivity, co, the area of the plates, A, and the gap between the plates, d. 14% Part (b) What is the numeric value, in picofarads, of the capacitance. 4 14% Part (c) With the information given, express the potential difference across the capacitor in terms of the magnitude of the charge on each plate, Q, and the capacitance, C. 14% Part (d) What is the numeric value, in volts, of the potential difference between the plates? 4 14% Part (e) If the charges on the plates are doubled to + 2Q and -2Q, then what is the value, in picofarads, of the capacitance? A 14% Part (f) If the area is doubled to 2A while the gap is decreased to - d, then what is the value, in picofarads, of the new capacitance? 14% Part (g) What is the new value, in volts, of potential difference between the plates with the original charges, +Q and -Q, given the increased area and reduced gap of Part (f)? AVnew Grade Summary Deductions Potential 100%