$9/19$ When you stand quietly, you pivot back and forth a very small amount about your ankles. It's easier to maintain stability if you tip slightly forward, so that your center of gravity is slightly in front of your ankles. The $80kg$ man shown in $($Figure $1)$ is $1\mathrm{.}8m$ tall; his center of gravity is $1\mathrm{.}0m$ above the ground and, during quiet standing, is $5\mathrm{.}5cm$ in front of his ankles.

Figure

$1$ of $1$

What is the magnitude of the gravitational torque about his ankles?

Express your answer with the appropriate units.

$=$

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