When you stand quietly, you pivot back and forth a very small amount about your ankles. It's easier to maintain stability if you tip slightly forward, so that your center of gravity is slightly in front of your ankles. The 80kg$80kg$ man $1)$ is 1.8m$1\mathrm{.}8m$ tall; his center of gravity is 1.0m$1\mathrm{.}0m$ above the ground and, during quiet standing, is 5.5cm$5\mathrm{.}5cm$ in front of his ankles.

What is the magnitude of the gravitational torque about his ankles?

Express your answer with the appropriate units.