Compute grade elevations at all full stations for an equal-tangent vertical curve with the following design...

 

Transcribed Image Text:

Compute grade elevations at all full stations for an equal-tangent vertical curve with the following design constraints. Report your elevations to the nearest hundredth of a foot and be sure to include the elevation check at the end of your computations (see section 4.4 of the textbook for more details). Station of PVI 35+20.00 Elevation of PVI 182.36 ft Station of PVI 63+50.00 2. (1 point) Using the same information listed in problem 1 above. Determine the elevation for a point on the curve at station 35+73. G₁ +4.5% 3. (1 point) Using the same information for the curve listed in problem 1 above. Compute the station and elevation of the highest point on the curve. Elevation of PVI 572.46 ft 4. (2 points) Compute the external distance (E), and the station and elevation of the lowest point for an unequal-tangent vertical curve with the following design parameters. Station of PVC 28+00.00 G₁ -3.0% Station of PVI 75+00.00 G₂ -3.7% Elevation of PVC 450.06 ft Length (L) 700 ft G₂ +5.0% 5. (2 points) Given the design constraints for an equal tangent vertical curve shown below. Calculate the length of the curve (L), to the nearest foot, such that it will also pass through a point, P, at station 32+00 with an elevation of 447.82 feet. Elevation of PVI 327.51 ft G₁ -2.2% G₁ -2.2% L₁ 300 ft 6. (2 points) Given the design constraints for an equal tangent vertical curve shown below. Calculate L (to the nearest foot) for the curve such that its turning point, (P) occurs at an elevation of 332.54 feet. G₂ +4.6% L2 500 ft G₂ +4.6% Compute grade elevations at all full stations for an equal-tangent vertical curve with the following design constraints. Report your elevations to the nearest hundredth of a foot and be sure to include the elevation check at the end of your computations (see section 4.4 of the textbook for more details). Station of PVI 35+20.00 Elevation of PVI 182.36 ft Station of PVI 63+50.00 2. (1 point) Using the same information listed in problem 1 above. Determine the elevation for a point on the curve at station 35+73. G₁ +4.5% 3. (1 point) Using the same information for the curve listed in problem 1 above. Compute the station and elevation of the highest point on the curve. Elevation of PVI 572.46 ft 4. (2 points) Compute the external distance (E), and the station and elevation of the lowest point for an unequal-tangent vertical curve with the following design parameters. Station of PVC 28+00.00 G₁ -3.0% Station of PVI 75+00.00 G₂ -3.7% Elevation of PVC 450.06 ft Length (L) 700 ft G₂ +5.0% 5. (2 points) Given the design constraints for an equal tangent vertical curve shown below. Calculate the length of the curve (L), to the nearest foot, such that it will also pass through a point, P, at station 32+00 with an elevation of 447.82 feet. Elevation of PVI 327.51 ft G₁ -2.2% G₁ -2.2% L₁ 300 ft 6. (2 points) Given the design constraints for an equal tangent vertical curve shown below. Calculate L (to the nearest foot) for the curve such that its turning point, (P) occurs at an elevation of 332.54 feet. G₂ +4.6% L2 500 ft G₂ +4.6%

Answer rating: 100% (QA)

The answer of the above asked questions is given below Answer and explanation 1 Using the given information we can calculate the elevation of the PVI ... View the full answer