A $0\mathrm{.}200-kg$ sample of aluminum is heated to $100C$ and placed into a cup containing $0\mathrm{.}300-kg$ of water initially at $30\mathrm{.}0C.$ The specific heat of water is $4186\frac{J}{kg*K},$ and the specific heat of aluminum is $910\frac{J}{kg*K}.$

Ignoring the container holding the water, find the final

equilibrium temperature $T$ of the aluminum and water, assuming no heat is lost to or gained by the environment.

$T=$

$C$