A $0\mathrm{.}250-kg$ aluminum bowl holding $0\mathrm{.}800$ kg of soup at $26\mathrm{.}8C$ is placed in a freezer. What is the final temperature if $424$ kJ of energy is transferred from the bowl and soup? Assume the soup has the same thermal properties as that of water, the specific heat of the liquid soup is $1\mathrm{.}00$kca$\frac{l}{kg*C},$ frozen soup is $0\mathrm{.}500$kca$\frac{l}{kg*C},$ and the latent heat of fusion is $79\mathrm{.}8$kca$\frac{l}{k}g.$ The specific heat of aluminum is $0\mathrm{.}215$kca$\frac{l}{kg*C}.$

$C$

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