A 0.025-kg bullet enters a 2.35-kg watermelon with a speed of 217 m/s and exits the...

 

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A 0.025-kg bullet enters a 2.35-kg watermelon with a speed of 217 m/s and exits the opposite side with a speed of 109 m/s. If the melon was originally at rest, then what speed will it have as the bullet leaves its opposite side? A 0.025-kg bullet enters a 2.35-kg watermelon with a speed of 217 m/s and exits the opposite side with a speed of 109 m/s. If the melon was originally at rest, then what speed will it have as the bullet leaves its opposite side?

Answer rating: 100% (QA)

To solve this problem we can apply the principle of conservation of momentum ... View the full answer