A 0.06 g of the NaCl sample (FM: 58.44) was treated with 15.00 mL of standard...
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A 0.06 g of the NaCl sample (FM: 58.44) was treated with 15.00 mL of standard 0.120 M AGNO, (FM: 169.872) solution. The excess silver was titrated with standard 0.211 M KSCN (FM: 97.182) solution, requiring 3.08 mL to reach the red Fe(SCN) end point. Calculate % of chloride (AM: 35.5) in the NaCl sample. NaCl(aq) + AGNO (aq)A9CI(s)+ NANO (aq) AGNO,(aq)+KSCN(aq) AGSCN(s) + KNO,(aq) * 50.00% 68.05% 92.89% 76.92% A 0.06 g of the NaCl sample (FM: 58.44) was treated with 15.00 mL of standard 0.120 M AGNO, (FM: 169.872) solution. The excess silver was titrated with standard 0.211 M KSCN (FM: 97.182) solution, requiring 3.08 mL to reach the red Fe(SCN) end point. Calculate % of chloride (AM: 35.5) in the NaCl sample. NaCl(aq) + AGNO (aq)A9CI(s)+ NANO (aq) AGNO,(aq)+KSCN(aq) AGSCN(s) + KNO,(aq) * 50.00% 68.05% 92.89% 76.92%
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Ans 6805 Explanation From the given reaction AgNO 3 KSCN AgSCN KNO 3 we can see 1 AgNO 3 requires 1 ... View the full answer
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