A .012 Kg bullet is fired horizontally into a 2 Kg block that is initially at rest on a table as shown. The bullets initial velocity is 300 m/s. The bullet remains embedded in the block and the two slide together until coming to reast a distance x to the right of the blocks initial position. The coefficient of kinetic friction between the block and the table is .40.

i) what is the initial kinetic energy of the block+bullet system before the collision?

ii) what distance x, would the block+bullet have to slide on the table to dissipate that energy?

iii) what is the initial momentum of the block+bullet system?

iv) By applying conservation of momentum, determine the actual speed of the block+bullet system immediately following the collision?

v) what is the actual kinetic energy of the block+ bullet immediately following the collision?

vi) what fraction of the initial kinetic energy is lost?

vii) what is the actual distance x that the block+bullet slides before coming to rest?

viii) how many times too great was the estimate of x based on the mistaken assumption that kinetic energy was conserved?

Answer rating: 100% (QA)

From the information above mass of the bullet m 1 0012 kg mass of the block m 2 2 kg bullet initial ... View the full answer