$A100-km,230-kVcircuit,$ calculate the ABCDz$=0\mathrm{.}0701+j0\mathrm{.}508\frac{}{k}m$ and a positive$-$sequence shunt

admitttance $ofy=j3\mathrm{.}33{10}^{-6}\frac{S}{k}m.$ Enter ABCD parameters $in$ polar form. Enter A and $Din$ per unit, $Bin,$ and $CinS.$ Enter the phase angles $in$ degrees.@$pu$

$B=,$@$,$@$$

$C=0\mathrm{.}0003316,$@$,$@$S$

$D=,$@$puk{V}_{LL}10\%.$ Double check your calculations. $k{V}_{LL}$

percent voltage regulation

Your response differs from the correct answer $by$ more than $10\%.$ Double check your calculations. $\%k{V}_{LL}k{V}_{LL}$

Your response differs from the correct answer $by$ more than $10\%.$ Double check your calculations. $\%k{V}_{LL}k{V}_{LL}$

$x$

The response you submitted has the wrong sign. $\%$

Answers in part b$-$d are wrong. Don't copy the line voltages aside from paer c and d