A $10-$ft boom is acted upon by the $930-lb$ force as shown in the figure.

Determine the tension in each cable and the reaction at the ball$-$and$-$socket joint at $A.$

The tension in cable $BD$ is $1218\mathrm{.}56$ lb$.$

$$

The tension in cable $BE$ is $$ lb$.$

The reaction at $A$ is $(1328\mathrm{.}22lb)i+(-620lb)j.($Include a minus sign if necessary.$)$

My answers are wrong, please walk me through a step by step