A $13-$centimeter pendulum moves according to the equation $=0\mathrm{.}19cos(6t),$ where $$ is the angular displacement from the vert displacement ${}_{\text{m}\text{a}\text{x}}$ and the rate of change of $($in $ra\frac{d}{sec})$ when $t=4$ seconds. $($Round your answers to three decimal places.$)$

${}_{\text{m}\text{a}\text{x}}=$

${}^{\text{'}}(4)=ra\frac{d}{sec}$