A ${13}^{\text{'}}$ long lifting bar, $AB,$ is used to lift a beam up into place. If the velocity of the lifting bar at point $A$ is $\frac{?}{\text{b}\text{a}\text{r}}(v_A)=(0\mathrm{.}6I)f\frac{t}{s},$ determine the following using instantaneous centers method, at the instant shown: $({}_{AB}=0\mathrm{.}05ra\frac{d}{s}$ and $v_B=(\frac{0\mathrm{.}25}{b}ar(J))f\frac{t}{s}$ and $($:$v_c=(0\mathrm{.}0417(\frac{?}{\text{b}\text{a}\text{r}}(i))+0\mathrm{.}5(\frac{?}{\text{b}\text{a}\text{r}}()))f\frac{t}{s}$