Question: A 100 kg artillery shell is fired with an initial velocity = 200 + 100. Ignore air resistance. It takes the shell 10 s to

A 100 kg artillery shell is fired with an initial velocity = 200 + 100. Ignore air resistance. It takes the shell 10 s to reach the highest point of its trajectory, where it explodes into two pieces, one four times more massive than the other. The heavier fragment lands directly below the point of the explosion. If the explosion exerts only forces in the horizontal direction, how far from the launch point, in , does the lighter fragment land? Use = 10 /2.

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