A 1000-lb object is released from rest 600 ft above the ground and allowed to fall...

 

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A 1000-lb object is released from rest 600 ft above the ground and allowed to fall under the influence of gravity. Assuming that the force in pounds due to air resistance is - 25v, where v is the velocity of the object in ft/sec, determine the equation of motion of the object. When will the object hit the ground? Assume that the acceleration due to gravity is 32 ft/sec and let x(t) represent the distance the object has fallen in t seconds. Determine the equation of motion of the object. x(t) = 40t - 50 (1 - e - 41/5) When will the object hit the ground? The object will hit the ground after seconds. (Round to three decimal places as needed.) A 1000-lb object is released from rest 600 ft above the ground and allowed to fall under the influence of gravity. Assuming that the force in pounds due to air resistance is - 25v, where v is the velocity of the object in ft/sec, determine the equation of motion of the object. When will the object hit the ground? Assume that the acceleration due to gravity is 32 ft/sec and let x(t) represent the distance the object has fallen in t seconds. Determine the equation of motion of the object. x(t) = 40t - 50 (1 - e - 41/5) When will the object hit the ground? The object will hit the ground after seconds. (Round to three decimal places as needed.)