( a) 2 = 1 - P 1 4.84 5 x 5 5. 11 1 = 1-Pl 484-5 0. 49 /18 0.49 / JB = > 1 - P ( 2 = 0. 63) + P LZ Power = 1 - Pl z s Q obj + Pl z st. 5) = 0.5339A manufacturer is interested in the output voltage of a power supply used in a PC. Output voltage is assumed to be normally distributed, with standard deviation 0.49 volt, and the manufacturer wishes to test H0 :,u = 5 volts against H1 3\" 5 volts, using n = 8 units. In your intermediate calculations, use z-scores rounded to two decimal places (e.g. 98.76). Round your answers to four decimal places (e.g. 98.7654). (a) The acceptance region is 4.84 S f S 5.11. Find the value of a. (b) Find the power of the test for detecting a true mean output voltage of 5.1 volts. (a) 0.4431