A 208-V two-pole 60-Hz Y-connected wound-rotor induction motor is rated at 15 hp. Its equivalent circuit components
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Question:
A 208-V two-pole 60-Hz Y-connected wound-rotor induction motor is rated at 15 hp. Its equivalent circuit components are
R 1 = 0.225 R 2 = 0.125 X M = 15.0
X 1 = 0.425 X 2 = 0.425
P mech = 300 W P misc = 0 P core = 250 W
For a slip of 0.075, find
(a) The line current I L
(b) The stator copper losses P SCL
(c) The air-gap power P AG
(d) The power converted from electrical to mechanical form P conv
(e) The induced torque τ ind
(f) The load torque τ load
(g) The overall machine efficiency
(h) The motor speed in revolutions per minute and radians per second
(i) What is the slip at the pullout torque?
(j) What is the pullout torque of this motor?
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