Question: A 3 . 5 - ft diameter concrete pipe ( n = 0 . 0 1 5 ) and longitudinal slope = 0 . 0

A 3.5-ft diameter concrete pipe (n=0.015) and longitudinal slope =0.0025 will be used to transport treated sanitary water. Gravitational acceleration is 32.2fs2. Design water depth =0.75 times the pipe diameter. Determine (show all equations and computations):
Water depth (Y) and How dischange (Q) for the required design water depth.
Top width (T) of the water surface at design water depth.
Hydranlic depth (D) and hydraulic radius (R4) at design water depth.
Average velocity (V) and Froude number (Fr) at design water depth.
State of the flow in the pipe at design water depth.
Critical depth (Yc) for the flow discharge already computed in this problem.
Verify if pipe meets requirements : V-2=2fts(deposition) and Vme=10fs(erosion).
Based on your results decide and explain your answer to justify if the pipe is appropriate for the proposed sanitary system.
A 3 . 5 - ft diameter concrete pipe ( n = 0 . 0 1

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Civil Engineering Questions!