A $45-mL$ sample of $0\mathrm{.}39MH\frac{C}{O}OH$ is titrated with $0\mathrm{.}39M$

KOH.

What is the $pH$ of the solution after $45mL$ of KOH has been

added to the acid?

$K_a(H\frac{C}{O}OH)=1\mathrm{.}77{10}^{-4}$

$($Hint: This titration will result in $H\frac{C}{O}OH$ to be converted to

Can you solve it ASAP, please?! A question like that will be on my exam. Please show your work step by step! Thank you very much!!