A $500$V dc generator with Ra$=0\mathrm{.}5$ and another $480$ V generator with Ra$=0\mathrm{.}4$ generate together $100$ KW to supply a load. Calculate the Share of the generators in KW and find the terminal Voltage.

Ans: Let G$1$ share m kilowatt and G$2(100-$m$)$ Kilo Watts.

I$1=1000$m$/$Eg$1=2$m$$ and I$2=1000(100-$m$)/480$ V $=208\mathrm{.}333-2\mathrm{.}08333$m$.$

From the equation V$=$Eg$1-$I$1.$Ra$1=$Eg$2-$i$2.$Ra$2$ we get $500-(2$m$)(0\mathrm{.}5)=480-(208\mathrm{.}333-2\mathrm{.}08333$m$).(0\mathrm{.}4)$;

We solve for m; then we solve for terminal voltage V