A $60-$kg mountain climber, starting from rest, climbs a vertical distance of $715$ m $.$ At the top, she is again at rest. In the process, her body generates $4\mathrm{.}3{10}^{6}J$ of energy via metabolic processes. In fact, her body acts like a heat engine, the efficiency of which is given by Equation $15\mathrm{.}11$ as $|)/(|||)Q_H||,$ where $|W|$ is the magnitude of the work she does and $|Q_H|$ is the magnitude of the input heat. Find her efficiency as a heat engine.

$e=$ Number $$ Units