Question: A 7 5 ohm line feeds a load which may exhibit two different normalised admittance at different times based on reasons out of the scope

75 ohm line feeds a load which may exhibit two different normalised admittance at different times based on reasons out of the scope of this question. The two normalized admittance is 0.3+j0.2 and 0.4 +0.7. You are asked to design a stub matching solution which is able to match both these admittances without changing the positions of the stub(s). The user will have the flexibility to change the length of the stub(s) to arrive at a match when the admittance switches. You have to suggest to the user the lengths of the stub(s), which will give good matching for each of the above two cases. The constraints given to you by the user is that when the load exhibits an admittance of 0.3+j0.2, the first stub is located at a distance of 0.13lambda away from the load. You are free to select a choice of any stub matching technique to arrive at an appropriate solution. The matching should be at a frequency of 1 GHz. 


Which method would you select and why? 


Draw the APLAC schematic of your solution when the normalised load admittance is 0.3+j0.2. All values must be clearly labelled in your schematic. 


Draw the APLAC schematic of your solution when the normalised load admittance is 0.4+j0.7. All values must be clearly labelled in your schematic.

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Stub Matching Method Selection In this situation a single openended stub matching technique is the most suitable choice for several reasons Flexibility By adjusting the length of the single stub we ca... View full answer

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