Question: (a) A continous random variable X has a pdf given by k(1+1), 1x <0 f(x)= 2k(1-x), 0x1 elsewhere 0, (i) Find the value of

(a) A continous random variable X has a pdf given by k(1+1),

(a) A continous random variable X has a pdf given by k(1+1), 1x

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a i Find the value of the constant k Since the pdf has to integrate to 1 over its support 0 x 1 we can use this property to find the constant k k integral from 0 to 1 of 21x dx 2 x 12x2 from 0 to 1 2 ... View full answer

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