A$-$ A propane $($C$3$H$8)$ burner releases gas at such a high rate that only half of it is combusted. Making the $($relatively unreasonable$)$ assumption that no CO is produced and that all of the hydrocarbons become CO$2$ and H$2$O$.$

Calculate:

$1-$ The equivalence ratio

$2-$ The fuel mixture fraction.

$3-$ The CO$2$ yield also briefly discusses the result if CO is produced.

B$-$ The propane burner mentioned in question $($a$)$ above is situated in a small combustion chamber with limited ventilation. The burner releases propane at a rate of $1\mathrm{.}35$ g$/$s and the measured air flow through the ventilation opening is $50$ g$/$s$.$ Assuming that all this air is used for combustion, calculate the equivalence ratio and the fuel mixture fraction.

$(($Please DO NOT copy$/$paste earlier answers asked in Cheqq.$))$