A balloon is connected to the ground by three cables as shown in the figure below. The force in cable DB is $2$ KN $.$ Given $F_{DA}=2\mathrm{.}18i+1\mathrm{.}09j-1\mathrm{.}743k(KN)$

The force $)$ as a vector is represented as

$0\mathrm{.}936i-0\mathrm{.}936j-1\mathrm{.}498k$

The projection of $F_{DA}$ along DB in KN is $0\mathrm{.}98$

The angle between DA and DB is $71\mathrm{.}82$

$1\mathrm{.}204i+1\mathrm{.}204j-1\mathrm{.}923k,1\mathrm{.}204i-1\mathrm{.}204j-1\mathrm{.}923k$

$,0\mathrm{.}936i+0\mathrm{.}936j-1\mathrm{.}498k$

$2\mathrm{.}13$

$65\mathrm{.}04$