Question: A balloon is rising vertically above a level, straight road at s(t) is increasing by ft/ sec. a constant rate of 2 ft/sec. Just when

A balloon is rising vertically above a level, straight road at s(t) is increasing by ft/ sec. a constant rate of 2 ft/sec. Just when the balloon is 76 ft (Simplify your answer.) above the ground, a bicycle moving at a constant rate of 11 ft/sec passes under it. How fast is the distance s(t) between the bicycle and balloon increasing 6 seconds later? (t) s(t) 0 x(t)
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