A bar of mass m and length L, is pivoted at the lower end and attached to two springs of equal elastic constant of restitution k. The springs are attached at the indicated positions and fixed to the walls as shown in the figure shown above, and when the bar is in a vertical position, the springs are at their natural length. Assume that the bar can rotate about the pivot free of friction and that the bar oscillates at the approximation of a small angle.
a) Draw the extended free body diagram of the bar out of the equilibrium position.
b) Using dynamical (not energetic) considerations, obtain the equation of motion of the bar.
c) Obtain the angular frequency of the bar, as a function of the mass m, the length L and the heights h1 and h2.
d) Keeping the position of the spring on the left fixed, raise or lower the spring on the right to make the period of oscillation of the bar increase?

Transcribed Image Text:

k k т h2 Pivote k k т h2 Pivote

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Here is your solution hope it helps Thanks In eqm springs will be in its natural Lengt... View the full answer