A biologist wants to make a coplot of LENGTH Vs WEIGHT given RIVER*SPECIES for fish caught...

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A biologist wants to make a coplot of LENGTH Vs WEIGHT given RIVER*SPECIES for fish caught in the Tennessee river and recorded in the DDT.csv data set, so that each point is colored according to the variable MILE which is treated as a factor (Qualitative variable). > head (ddt) RIVER MILE SPECIES LENGTH WEIGHT DDT 5 CCATFISH 732 10 42.5 44.0 5 CCATFISH 5 CCATFISH 41.5 795 16 547 23 465 21 5 CCATFISH 39.0 5 CCATFISH 50.5 1252 50 5 CCATFISH 52.0 1255 150 1 FCM 2 FCM 3 FCM 4 FCM 5 FCM 6 FCM # The following code may help m=with (ddt, as.numeric (factor (MILE))) # A length (unique (m)) #B (a) Make the coplot as the biologist required Hint: Use coplot (), Lab 1, the code provided, and plotting options pch and col to differentiate the MILE variable. You should be able to produce something like what is shown below (b) Interpret the lower left three conditional plots. (c) What does line A do? (d) What does line B do? Why are the top six plots empty? (f) What is the mean value of DDT found in the sample of CCATFISH caught in the FCM river? Hint: ddt=read.csv ("..\\CSV\\DDT.csv") head (ddt) subset (ddt, RIVER=="FCM" & SPECIES=="CCATFISH",) #or ddt [ddt$RIVER=="FCM" & ddt $SPECIES=="CCATFISH",] WEIGHT 500 1500 500 1500 20 30 0 40 00. 00 Bo CCATFISH 50 00 08.00 20 LENGTH 30 0 40 LMBASS TT 50 Given SPECIES 20 TT 30 OF 40 SMBUFFALO 50 oks 0 500 1500 500 1500 FCM LCM SCM TRM Given: RIVER A biologist wants to make a coplot of LENGTH Vs WEIGHT given RIVER*SPECIES for fish caught in the Tennessee river and recorded in the DDT.csv data set, so that each point is colored according to the variable MILE which is treated as a factor (Qualitative variable). > head (ddt) RIVER MILE SPECIES LENGTH WEIGHT DDT 5 CCATFISH 732 10 42.5 44.0 5 CCATFISH 5 CCATFISH 41.5 795 16 547 23 465 21 5 CCATFISH 39.0 5 CCATFISH 50.5 1252 50 5 CCATFISH 52.0 1255 150 1 FCM 2 FCM 3 FCM 4 FCM 5 FCM 6 FCM # The following code may help m=with (ddt, as.numeric (factor (MILE))) # A length (unique (m)) #B (a) Make the coplot as the biologist required Hint: Use coplot (), Lab 1, the code provided, and plotting options pch and col to differentiate the MILE variable. You should be able to produce something like what is shown below (b) Interpret the lower left three conditional plots. (c) What does line A do? (d) What does line B do? Why are the top six plots empty? (f) What is the mean value of DDT found in the sample of CCATFISH caught in the FCM river? Hint: ddt=read.csv ("..\\CSV\\DDT.csv") head (ddt) subset (ddt, RIVER=="FCM" & SPECIES=="CCATFISH",) #or ddt [ddt$RIVER=="FCM" & ddt $SPECIES=="CCATFISH",] WEIGHT 500 1500 500 1500 20 30 0 40 00. 00 Bo CCATFISH 50 00 08.00 20 LENGTH 30 0 40 LMBASS TT 50 Given SPECIES 20 TT 30 OF 40 SMBUFFALO 50 oks 0 500 1500 500 1500 FCM LCM SCM TRM Given: RIVER

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a What are the categorical variables The variables ... View the full answer