A block moves in simple harmonic motion with a frequency of $2\mathrm{.}80$ Hz and an amplitude of $5\mathrm{.}80$ cm$.$

$($a$)$

Through what total distance $($in cm$)$ does the block move during one cycle of its motion?

Imagine the object starts at one of the maximum displacement points. The distance of twice the amplitude is traveled from the first maximum displacement point to the second on the other side of the equilibrium point. How much farther must the object travel to reach its starting point again? cm