A block slides down a frictionless ramp that is at an angle of 45 degrees with...
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A block slides down a frictionless ramp that is at an angle of 45 degrees with respect to the ground. It begins at rest. To answer the following questions, assume that the block has traveled ten meters along the ramp by time "t". a. How much work has been done by gravity in this time? i. h = 10sin 45° meter ii. mgh = m* g * 10 sin45° = 5√2mg = 69.296mJ b. Using the kinematic equations for constant acceleration, how fast will the block be going at time "t"? masin45° ma gsin45° = a a = = √√₂ -g (m/s²) = 6.9296 m/s² 2 =√gt (m/s) = 6.9296t (m/s) v = v,+ at = f c. Repeat the calculation from part (b) using conservation of energy. i./mv² = 5√2mg 1 2 ii. /v² = 5√2g 2 2 iii. v² = 10√/2g iv. v 11.77 m/s A block slides down a frictionless ramp that is at an angle of 45 degrees with respect to the ground. It begins at rest. To answer the following questions, assume that the block has traveled ten meters along the ramp by time "t". a. How much work has been done by gravity in this time? i. h = 10sin 45° meter ii. mgh = m* g * 10 sin45° = 5√2mg = 69.296mJ b. Using the kinematic equations for constant acceleration, how fast will the block be going at time "t"? masin45° ma gsin45° = a a = = √√₂ -g (m/s²) = 6.9296 m/s² 2 =√gt (m/s) = 6.9296t (m/s) v = v,+ at = f c. Repeat the calculation from part (b) using conservation of energy. i./mv² = 5√2mg 1 2 ii. /v² = 5√2g 2 2 iii. v² = 10√/2g iv. v 11.77 m/s
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Related Book For
Fundamentals of Physics
ISBN: 978-0471758013
8th Extended edition
Authors: Jearl Walker, Halliday Resnick
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