Question: A bowling ball is suspended from the ceiling using a light string. While the string is taut, the ball is pulled back so that the

A bowling ball is suspended from the ceiling using a light string. While the string is taut, the ball is pulled back so that the string makes an angle of I9 = 6.5 with respect to the vertical, and then the ball is released from rest. The resulting period of oscillation is T = 3.3 s. What is the speed of the bowling ball at the bottom of its swing? For the limit check, investigate what happens to the ball's speed at the bottom if it is barely pulled back at all before being released (:9 ) 0). Representation: 0 1 2 Physics Concept(s): 0 1 2 Initial Equation(s): 0 0.5 1 Symbolic Answer: 0 1 Units Check: 0 0.5 1 Limits Check: 0 0.5 1 Neatness: -2 -1 0 Total: Correct Answer: Y N Representation Physics Concept(s) (Refer to the list posted on Carmen) (1) (2) Initial Equations Algebra Work (Symbols only. Don't plug in any numbers yet.) Symbolic Answer: Units Check Numerical Answer: Limits Check a) As 6 > 0, what limit does 1; approach? b) Why does the result make physical sense? (Obtain this by plugging numbers into your symbolic answer.)

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