Question: a] By hand, solve problem 24.46 (81 ed) in the C80: text using the multiple application trapezoidal rule. Replace the first data point with e=0.00,

 a] By hand, solve problem 24.46 (81" ed) in the C80:text using the multiple application trapezoidal rule. Replace the first data pointwith e=0.00, 5240.0. 0.02 40.0 0.05 37.5 0.10 43.0 Rupture 0.15 52.0

60 0.20 60.0 0.25 55.0 40 s. ksi Modulus of 20 toughness0 0.1 0.2 (a) (b) FIGURE P24.46 (a) A rod under axialloading and (b) the resulting stress-strain curve where stress is in kips

a] By hand, solve problem 24.46 (81" ed) in the C80: text using the multiple application trapezoidal rule. Replace the first data point with e=0.00, 5240.0. 0.02 40.0 0.05 37.5 0.10 43.0 Rupture 0.15 52.0 60 0.20 60.0 0.25 55.0 40 s. ksi Modulus of 20 toughness 0 0.1 0.2 (a) (b) FIGURE P24.46 (a) A rod under axial loading and (b) the resulting stress-strain curve where stress is in kips per square inch (10 Ib/in?) and strain is dimensionless.24.415 A. rod subject to an axial load (Fig. P24.4orr} will be de- formed, as shown in the stress-strain curve in Fig. F24.-=lob. The area under the curve from zero stress out to the point of rupture is called the modulus of roughness of the material. It provides a measure of the energy,r per unit volume required to cause the mate- rial to rupture. As such. it is representative of the material's abil- itj.r to withstand an impact load. Use numerical integration to compute the modulus of toughness for the stress- strain curve seen in Fi . amass

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